If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+10x-9000=0
a = 3; b = 10; c = -9000;
Δ = b2-4ac
Δ = 102-4·3·(-9000)
Δ = 108100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108100}=\sqrt{100*1081}=\sqrt{100}*\sqrt{1081}=10\sqrt{1081}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{1081}}{2*3}=\frac{-10-10\sqrt{1081}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{1081}}{2*3}=\frac{-10+10\sqrt{1081}}{6} $
| 2/7=1/3+1/a | | 5(x+4)=5 | | 3x^2-10x+9000=0 | | -10x/(+2/5)=0 | | -10/(+2x/5)=0 | | 8=1000+3x | | 8(x-1)=(6x-26) | | x*5-32=x*3-10 | | y+×=405 | | (16,5+13x)-15x=0 | | 16x-128=-4x+-152 | | 70x^2+21x-7=0 | | 4*(x+5)=36 | | 1/2x+7/5=3+1/5x | | m+87=403 | | 4x=2x= | | 8x+4x^2=240 | | 2^x-3.3^2x-8=36 | | 5x4+4=4x4+3 | | 4x/x4-1=0 | | 55852,05=600*x^2,25 | | -15x^2+42x-24=0 | | 3(x−9)(x−2)−(x−7)(x−9)=0 | | a*3+6=1 | | x+22=4+3x | | 4x+3=24+x | | 3z/7+2=3 | | (x+1)(x+1)-(5-4x)(5-4x)=0 | | a/6+8=9 | | (x+1)^2-(5-4x)^2=0 | | 5-3x=10-6x | | 0.1h+2=h+0.2 |